Proof: Byte 124 Stays the Same 17

Let's prove the following theorem:

if the following are true:

instruction #4 is add dst=3 src1=3 src2=4
the PC at time 17 = 4
value of cell 124 at time 17 = 3

then value of cell 124 at time 18 = 3

Proof:

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Given

1	instruction #4 is `add dst=3 src1=3 src2=4`
2	the PC at time 17 = 4
3	value of cell 124 at time 17 = 3

Proof Table

#	Claim	Reason
1	not (124 = 3)	not (124 = 3) (Fixed Value Statement)
2	value of cell 124 at time (17 + 1) = value of cell 124 at time 17	if instruction #4 is `add dst=3 src1=3 src2=4` and the PC at time 17 = 4 and not (124 = 3), then value of cell 124 at time (17 + 1) = value of cell 124 at time 17 (ADD Instruction Property 2)
3	17 + 1 = 18	17 + 1 = 18 (Fixed Value Statement)
4	value of cell 124 at time (17 + 1) = value of cell 124 at time 18	if 17 + 1 = 18, then value of cell 124 at time (17 + 1) = value of cell 124 at time 18 (Substitution)
5	value of cell 124 at time 18 = value of cell 124 at time 17	if value of cell 124 at time (17 + 1) = value of cell 124 at time 18 and value of cell 124 at time (17 + 1) = value of cell 124 at time 17, then value of cell 124 at time 18 = value of cell 124 at time 17 (Transitive Property of Equality Variation 2)
6	value of cell 124 at time 18 = 3	if value of cell 124 at time 18 = value of cell 124 at time 17 and value of cell 124 at time 17 = 3, then value of cell 124 at time 18 = 3 (Transitive Property of Equality)

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