Proof: Byte 125 Stays the Same 16

Let's prove the following theorem:

if the following are true:
  • instruction #3 is load dst=4 addr=1 imm=0
  • the PC at time 16 = 3
  • value of cell 125 at time 16 = 2

then value of cell 125 at time 17 = 2

Proof:

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Given
1 instruction #3 is load dst=4 addr=1 imm=0
2 the PC at time 16 = 3
3 value of cell 125 at time 16 = 2
Proof Table
# Claim Reason
1 not (125 = 4) not (125 = 4)
2 value of cell 125 at time (16 + 1) = value of cell 125 at time 16 if instruction #3 is load dst=4 addr=1 imm=0 and the PC at time 16 = 3 and not (125 = 4), then value of cell 125 at time (16 + 1) = value of cell 125 at time 16
3 16 + 1 = 17 16 + 1 = 17
4 value of cell 125 at time (16 + 1) = value of cell 125 at time 17 if 16 + 1 = 17, then value of cell 125 at time (16 + 1) = value of cell 125 at time 17
5 value of cell 125 at time 17 = value of cell 125 at time 16 if value of cell 125 at time (16 + 1) = value of cell 125 at time 17 and value of cell 125 at time (16 + 1) = value of cell 125 at time 16, then value of cell 125 at time 17 = value of cell 125 at time 16
6 value of cell 125 at time 17 = 2 if value of cell 125 at time 17 = value of cell 125 at time 16 and value of cell 125 at time 16 = 2, then value of cell 125 at time 17 = 2

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