Proof: Byte 127 Stays the Same 22
Let's prove the following theorem:
if the following are true:
- instruction #22 is
addi dst=1 src=1 imm=3
- the PC at time 22 = 22
- value of cell 127 at time 22 = 2
then value of cell 127 at time 23 = 2
Proof:
Given
1 | instruction #22 is addi dst=1 src=1 imm=3 |
---|---|
2 | the PC at time 22 = 22 |
3 | value of cell 127 at time 22 = 2 |
# | Claim | Reason |
---|---|---|
1 | not (127 = 1) | not (127 = 1) |
2 | value of cell 127 at time (22 + 1) = value of cell 127 at time 22 | if instruction #22 is addi dst=1 src=1 imm=3 and the PC at time 22 = 22 and not (127 = 1), then value of cell 127 at time (22 + 1) = value of cell 127 at time 22 |
3 | 22 + 1 = 23 | 22 + 1 = 23 |
4 | value of cell 127 at time (22 + 1) = value of cell 127 at time 23 | if 22 + 1 = 23, then value of cell 127 at time (22 + 1) = value of cell 127 at time 23 |
5 | value of cell 127 at time 23 = value of cell 127 at time 22 | if value of cell 127 at time (22 + 1) = value of cell 127 at time 23 and value of cell 127 at time (22 + 1) = value of cell 127 at time 22, then value of cell 127 at time 23 = value of cell 127 at time 22 |
6 | value of cell 127 at time 23 = 2 | if value of cell 127 at time 23 = value of cell 127 at time 22 and value of cell 127 at time 22 = 2, then value of cell 127 at time 23 = 2 |
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