Proof: Byte 2 Stays the Same 16

Let's prove the following theorem:

if the following are true:

instruction #3 is load dst=4 addr=1 imm=0
the PC at time 16 = 3
value of cell 2 at time 16 = 21

then value of cell 2 at time 17 = 21

Proof:

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Given

1	instruction #3 is `load dst=4 addr=1 imm=0`
2	the PC at time 16 = 3
3	value of cell 2 at time 16 = 21

Proof Table

#	Claim	Reason
1	not (2 = 4)	not (2 = 4) (Fixed Value Statement)
2	value of cell 2 at time (16 + 1) = value of cell 2 at time 16	if instruction #3 is `load dst=4 addr=1 imm=0` and the PC at time 16 = 3 and not (2 = 4), then value of cell 2 at time (16 + 1) = value of cell 2 at time 16 (LOAD Instruction Property 2)
3	16 + 1 = 17	16 + 1 = 17 (Fixed Value Statement)
4	value of cell 2 at time (16 + 1) = value of cell 2 at time 17	if 16 + 1 = 17, then value of cell 2 at time (16 + 1) = value of cell 2 at time 17 (Substitution)
5	value of cell 2 at time 17 = value of cell 2 at time 16	if value of cell 2 at time (16 + 1) = value of cell 2 at time 17 and value of cell 2 at time (16 + 1) = value of cell 2 at time 16, then value of cell 2 at time 17 = value of cell 2 at time 16 (Transitive Property of Equality Variation 2)
6	value of cell 2 at time 17 = 21	if value of cell 2 at time 17 = value of cell 2 at time 16 and value of cell 2 at time 16 = 21, then value of cell 2 at time 17 = 21 (Transitive Property of Equality)

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