Proof: Pc 11

Let's prove the following theorem:

if the following are true:

instruction #17 is load dst=3 addr=1 imm=1
the PC at time 11 = 17

then the PC at time 12 = 18

Proof:

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Given

1	instruction #17 is `load dst=3 addr=1 imm=1`
2	the PC at time 11 = 17

Proof Table

#	Claim	Reason
1	the PC at time (11 + 1) = 17 + 1	if instruction #17 is `load dst=3 addr=1 imm=1` and the PC at time 11 = 17, then the PC at time (11 + 1) = 17 + 1 (LOAD Instruction Property 3)
2	11 + 1 = 12	11 + 1 = 12 (Fixed Value Statement)
3	17 + 1 = 18	17 + 1 = 18 (Fixed Value Statement)
4	the PC at time (11 + 1) = the PC at time 12	if 11 + 1 = 12, then the PC at time (11 + 1) = the PC at time 12 (Substitution)
5	the PC at time 12 = 18	if the PC at time (11 + 1) = 17 + 1 and the PC at time (11 + 1) = the PC at time 12 and 17 + 1 = 18, then the PC at time 12 = 18 (Transitive Property Application 2)

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