Proof: Pc 16

Let's prove the following theorem:

if the following are true:

instruction #3 is load dst=4 addr=1 imm=0
the PC at time 16 = 3

then the PC at time 17 = 4

Proof:

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Given

1	instruction #3 is `load dst=4 addr=1 imm=0`
2	the PC at time 16 = 3

Proof Table

#	Claim	Reason
1	the PC at time (16 + 1) = 3 + 1	if instruction #3 is `load dst=4 addr=1 imm=0` and the PC at time 16 = 3, then the PC at time (16 + 1) = 3 + 1 (LOAD Instruction Property 3)
2	16 + 1 = 17	16 + 1 = 17 (Fixed Value Statement)
3	3 + 1 = 4	3 + 1 = 4 (Fixed Value Statement)
4	the PC at time (16 + 1) = the PC at time 17	if 16 + 1 = 17, then the PC at time (16 + 1) = the PC at time 17 (Substitution)
5	the PC at time 17 = 4	if the PC at time (16 + 1) = 3 + 1 and the PC at time (16 + 1) = the PC at time 17 and 3 + 1 = 4, then the PC at time 17 = 4 (Transitive Property Application 2)

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