Proof: Pc 7
Let's prove the following theorem:
if the following are true:
- instruction #13 is
store src=3 addr=1 imm=0 - the PC at time 7 = 13
then the PC at time 8 = 14
Proof:
Given
| 1 | instruction #13 is store src=3 addr=1 imm=0 |
|---|---|
| 2 | the PC at time 7 = 13 |
| # | Claim | Reason |
|---|---|---|
| 1 | the PC at time (7 + 1) = 13 + 1 | if instruction #13 is store src=3 addr=1 imm=0 and the PC at time 7 = 13, then the PC at time (7 + 1) = 13 + 1 |
| 2 | 7 + 1 = 8 | 7 + 1 = 8 |
| 3 | 13 + 1 = 14 | 13 + 1 = 14 |
| 4 | the PC at time (7 + 1) = the PC at time 8 | if 7 + 1 = 8, then the PC at time (7 + 1) = the PC at time 8 |
| 5 | the PC at time 8 = 14 | if the PC at time (7 + 1) = 13 + 1 and the PC at time (7 + 1) = the PC at time 8 and 13 + 1 = 14, then the PC at time 8 = 14 |
Comments
Please log in to add comments