Proof: Pc 8

Let's prove the following theorem:

if the following are true:

instruction #14 is load dst=3 addr=1 imm=1
the PC at time 8 = 14

then the PC at time 9 = 15

Proof:

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Given

1	instruction #14 is `load dst=3 addr=1 imm=1`
2	the PC at time 8 = 14

Proof Table

#	Claim	Reason
1	the PC at time (8 + 1) = 14 + 1	if instruction #14 is `load dst=3 addr=1 imm=1` and the PC at time 8 = 14, then the PC at time (8 + 1) = 14 + 1 (LOAD Instruction Property 3)
2	8 + 1 = 9	8 + 1 = 9 (Fixed Value Statement)
3	14 + 1 = 15	14 + 1 = 15 (Fixed Value Statement)
4	the PC at time (8 + 1) = the PC at time 9	if 8 + 1 = 9, then the PC at time (8 + 1) = the PC at time 9 (Substitution)
5	the PC at time 9 = 15	if the PC at time (8 + 1) = 14 + 1 and the PC at time (8 + 1) = the PC at time 9 and 14 + 1 = 15, then the PC at time 9 = 15 (Transitive Property Application 2)

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