Proof: Addi Insn 6
Let's prove the following theorem:
if the following are true:
- instruction #6 is
addi dst=2 src=3 imm=0
- the PC at time 6 = 6
- value of cell 3 at time 6 = 1
then value of cell 2 at time 7 = 1
Instructions
Memory Cells |
---|
Program Counter | Time |
---|---|
0 | 0 |
LW Computer Simulator
Proof:
Given
1 | instruction #6 is addi dst=2 src=3 imm=0 |
---|---|
2 | the PC at time 6 = 6 |
3 | value of cell 3 at time 6 = 1 |
# | Claim | Reason |
---|---|---|
1 | value of cell 2 at time (6 + 1) = (value of cell 3 at time 6) + 0 | if instruction #6 is addi dst=2 src=3 imm=0 and the PC at time 6 = 6, then value of cell 2 at time (6 + 1) = (value of cell 3 at time 6) + 0 |
2 | 6 + 1 = 7 | 6 + 1 = 7 |
3 | value of cell 2 at time (6 + 1) = value of cell 2 at time 7 | if 6 + 1 = 7, then value of cell 2 at time (6 + 1) = value of cell 2 at time 7 |
4 | value of cell 2 at time 7 = (value of cell 3 at time 6) + 0 | if value of cell 2 at time (6 + 1) = value of cell 2 at time 7 and value of cell 2 at time (6 + 1) = (value of cell 3 at time 6) + 0, then value of cell 2 at time 7 = (value of cell 3 at time 6) + 0 |
5 | value of cell 2 at time 7 = 1 + 0 | if value of cell 2 at time 7 = (value of cell 3 at time 6) + 0 and value of cell 3 at time 6 = 1, then value of cell 2 at time 7 = 1 + 0 |
6 | 1 + 0 = 1 | 1 + 0 = 1 |
7 | value of cell 2 at time 7 = 1 | if value of cell 2 at time 7 = 1 + 0 and 1 + 0 = 1, then value of cell 2 at time 7 = 1 |
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