Proof: Beq No Branch 14
Let's prove the following theorem:
if the following are true:
- instruction #8 is
beq left=4 right=5 imm=1
- the PC at time 14 = 8
- value of cell 4 at time 14 = 2
- value of cell 5 at time 14 = 4
then the PC at time 15 = 9
Instructions
Memory Cells |
---|
Program Counter | Time |
---|---|
0 | 0 |
LW Computer Simulator
Proof:
Given
1 | instruction #8 is beq left=4 right=5 imm=1 |
---|---|
2 | the PC at time 14 = 8 |
3 | value of cell 4 at time 14 = 2 |
4 | value of cell 5 at time 14 = 4 |
# | Claim | Reason |
---|---|---|
1 | value of cell 4 at time 14 = 4 = 2 = 4 | if value of cell 4 at time 14 = 2, then value of cell 4 at time 14 = 4 = 2 = 4 |
2 | not (value of cell 4 at time 14 = 4) = not (2 = 4) | if value of cell 4 at time 14 = 4 = 2 = 4, then not (value of cell 4 at time 14 = 4) = not (2 = 4) |
3 | not (2 = 4) | not (2 = 4) |
4 | not (value of cell 4 at time 14 = 4) | if not (2 = 4) and not (value of cell 4 at time 14 = 4) = not (2 = 4), then not (value of cell 4 at time 14 = 4) |
5 | value of cell 4 at time 14 = value of cell 5 at time 14 = value of cell 4 at time 14 = 4 | if value of cell 5 at time 14 = 4, then value of cell 4 at time 14 = value of cell 5 at time 14 = value of cell 4 at time 14 = 4 |
6 | not (value of cell 4 at time 14 = value of cell 5 at time 14) = not (value of cell 4 at time 14 = 4) | if value of cell 4 at time 14 = value of cell 5 at time 14 = value of cell 4 at time 14 = 4, then not (value of cell 4 at time 14 = value of cell 5 at time 14) = not (value of cell 4 at time 14 = 4) |
7 | not (value of cell 4 at time 14 = value of cell 5 at time 14) | if not (value of cell 4 at time 14 = 4) and not (value of cell 4 at time 14 = value of cell 5 at time 14) = not (value of cell 4 at time 14 = 4), then not (value of cell 4 at time 14 = value of cell 5 at time 14) |
8 | the PC at time (14 + 1) = 8 + 1 | if instruction #8 is beq left=4 right=5 imm=1 and the PC at time 14 = 8 and not (value of cell 4 at time 14 = value of cell 5 at time 14), then the PC at time (14 + 1) = 8 + 1 |
9 | 14 + 1 = 15 | 14 + 1 = 15 |
10 | the PC at time (14 + 1) = the PC at time 15 | if 14 + 1 = 15, then the PC at time (14 + 1) = the PC at time 15 |
11 | 8 + 1 = 9 | 8 + 1 = 9 |
12 | the PC at time 15 = 9 | if the PC at time (14 + 1) = 8 + 1 and the PC at time (14 + 1) = the PC at time 15 and 8 + 1 = 9, then the PC at time 15 = 9 |
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