Proof: Beq No Branch 14
Let's prove the following theorem:
if the following are true:
- instruction #8 is
beq left=4 right=5 imm=1 - the PC at time 14 = 8
- value of cell 4 at time 14 = 2
- value of cell 5 at time 14 = 4
then the PC at time 15 = 9
Instructions
| Memory Cells |
|---|
| Program Counter | Time |
|---|---|
| 0 | 0 |
LW Computer Simulator
Proof:
Given
| 1 | instruction #8 is beq left=4 right=5 imm=1 |
|---|---|
| 2 | the PC at time 14 = 8 |
| 3 | value of cell 4 at time 14 = 2 |
| 4 | value of cell 5 at time 14 = 4 |
| # | Claim | Reason |
|---|---|---|
| 1 | value of cell 4 at time 14 = 4 = 2 = 4 | if value of cell 4 at time 14 = 2, then value of cell 4 at time 14 = 4 = 2 = 4 |
| 2 | not (value of cell 4 at time 14 = 4) = not (2 = 4) | if value of cell 4 at time 14 = 4 = 2 = 4, then not (value of cell 4 at time 14 = 4) = not (2 = 4) |
| 3 | not (2 = 4) | not (2 = 4) |
| 4 | not (value of cell 4 at time 14 = 4) | if not (2 = 4) and not (value of cell 4 at time 14 = 4) = not (2 = 4), then not (value of cell 4 at time 14 = 4) |
| 5 | value of cell 4 at time 14 = value of cell 5 at time 14 = value of cell 4 at time 14 = 4 | if value of cell 5 at time 14 = 4, then value of cell 4 at time 14 = value of cell 5 at time 14 = value of cell 4 at time 14 = 4 |
| 6 | not (value of cell 4 at time 14 = value of cell 5 at time 14) = not (value of cell 4 at time 14 = 4) | if value of cell 4 at time 14 = value of cell 5 at time 14 = value of cell 4 at time 14 = 4, then not (value of cell 4 at time 14 = value of cell 5 at time 14) = not (value of cell 4 at time 14 = 4) |
| 7 | not (value of cell 4 at time 14 = value of cell 5 at time 14) | if not (value of cell 4 at time 14 = 4) and not (value of cell 4 at time 14 = value of cell 5 at time 14) = not (value of cell 4 at time 14 = 4), then not (value of cell 4 at time 14 = value of cell 5 at time 14) |
| 8 | the PC at time (14 + 1) = 8 + 1 | if instruction #8 is beq left=4 right=5 imm=1 and the PC at time 14 = 8 and not (value of cell 4 at time 14 = value of cell 5 at time 14), then the PC at time (14 + 1) = 8 + 1 |
| 9 | 14 + 1 = 15 | 14 + 1 = 15 |
| 10 | the PC at time (14 + 1) = the PC at time 15 | if 14 + 1 = 15, then the PC at time (14 + 1) = the PC at time 15 |
| 11 | 8 + 1 = 9 | 8 + 1 = 9 |
| 12 | the PC at time 15 = 9 | if the PC at time (14 + 1) = 8 + 1 and the PC at time (14 + 1) = the PC at time 15 and 8 + 1 = 9, then the PC at time 15 = 9 |
Comments
Please log in to add comments