Proof: Byte 2 Stays the Same 14
Let's prove the following theorem:
if the following are true:
- instruction #8 is
beq left=4 right=5 imm=1
- the PC at time 14 = 8
- value of cell 2 at time 14 = 2
then value of cell 2 at time 15 = 2
Instructions
Memory Cells |
---|
Program Counter | Time |
---|---|
0 | 0 |
LW Computer Simulator
Proof:
Given
1 | instruction #8 is beq left=4 right=5 imm=1 |
---|---|
2 | the PC at time 14 = 8 |
3 | value of cell 2 at time 14 = 2 |
# | Claim | Reason |
---|---|---|
1 | value of cell 2 at time (14 + 1) = value of cell 2 at time 14 | if instruction #8 is beq left=4 right=5 imm=1 and the PC at time 14 = 8, then value of cell 2 at time (14 + 1) = value of cell 2 at time 14 |
2 | 14 + 1 = 15 | 14 + 1 = 15 |
3 | value of cell 2 at time (14 + 1) = value of cell 2 at time 15 | if 14 + 1 = 15, then value of cell 2 at time (14 + 1) = value of cell 2 at time 15 |
4 | value of cell 2 at time 15 = value of cell 2 at time 14 | if value of cell 2 at time (14 + 1) = value of cell 2 at time 15 and value of cell 2 at time (14 + 1) = value of cell 2 at time 14, then value of cell 2 at time 15 = value of cell 2 at time 14 |
5 | value of cell 2 at time 15 = 2 | if value of cell 2 at time 15 = value of cell 2 at time 14 and value of cell 2 at time 14 = 2, then value of cell 2 at time 15 = 2 |
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