Proof: Byte 3 Stays the Same 6

Let's prove the following theorem:

if the following are true:
  • instruction #6 is addi dst=2 src=3 imm=0
  • the PC at time 6 = 6
  • value of cell 3 at time 6 = 1

then value of cell 3 at time 7 = 1

Instructions
Memory Cells
Program Counter Time
0 0
LW Computer Simulator

Proof:

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Given
1 instruction #6 is addi dst=2 src=3 imm=0
2 the PC at time 6 = 6
3 value of cell 3 at time 6 = 1
Proof Table
# Claim Reason
1 not (3 = 2) not (3 = 2)
2 value of cell 3 at time (6 + 1) = value of cell 3 at time 6 if instruction #6 is addi dst=2 src=3 imm=0 and the PC at time 6 = 6 and not (3 = 2), then value of cell 3 at time (6 + 1) = value of cell 3 at time 6
3 6 + 1 = 7 6 + 1 = 7
4 value of cell 3 at time (6 + 1) = value of cell 3 at time 7 if 6 + 1 = 7, then value of cell 3 at time (6 + 1) = value of cell 3 at time 7
5 value of cell 3 at time 7 = value of cell 3 at time 6 if value of cell 3 at time (6 + 1) = value of cell 3 at time 7 and value of cell 3 at time (6 + 1) = value of cell 3 at time 6, then value of cell 3 at time 7 = value of cell 3 at time 6
6 value of cell 3 at time 7 = 1 if value of cell 3 at time 7 = value of cell 3 at time 6 and value of cell 3 at time 6 = 1, then value of cell 3 at time 7 = 1

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