Proof: Byte 4 Stays the Same 5
Let's prove the following theorem:
if the following are true:
- instruction #5 is
addi dst=1 src=2 imm=0
- the PC at time 5 = 5
- value of cell 4 at time 5 = 0
then value of cell 4 at time 6 = 0
Instructions
Memory Cells |
---|
Program Counter | Time |
---|---|
0 | 0 |
LW Computer Simulator
Proof:
Given
1 | instruction #5 is addi dst=1 src=2 imm=0 |
---|---|
2 | the PC at time 5 = 5 |
3 | value of cell 4 at time 5 = 0 |
# | Claim | Reason |
---|---|---|
1 | not (4 = 1) | not (4 = 1) |
2 | value of cell 4 at time (5 + 1) = value of cell 4 at time 5 | if instruction #5 is addi dst=1 src=2 imm=0 and the PC at time 5 = 5 and not (4 = 1), then value of cell 4 at time (5 + 1) = value of cell 4 at time 5 |
3 | 5 + 1 = 6 | 5 + 1 = 6 |
4 | value of cell 4 at time (5 + 1) = value of cell 4 at time 6 | if 5 + 1 = 6, then value of cell 4 at time (5 + 1) = value of cell 4 at time 6 |
5 | value of cell 4 at time 6 = value of cell 4 at time 5 | if value of cell 4 at time (5 + 1) = value of cell 4 at time 6 and value of cell 4 at time (5 + 1) = value of cell 4 at time 5, then value of cell 4 at time 6 = value of cell 4 at time 5 |
6 | value of cell 4 at time 6 = 0 | if value of cell 4 at time 6 = value of cell 4 at time 5 and value of cell 4 at time 5 = 0, then value of cell 4 at time 6 = 0 |
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