Proof: Pc 18
Let's prove the following theorem:
if the following are true:
    
    - instruction #6 is addi dst=2 src=3 imm=0
- the PC at time 18 = 6
then the PC at time 19 = 7
Instructions
        
    | Memory Cells | 
|---|
| Program Counter | Time | 
|---|---|
| 0 | 0 | 
  
  
LW Computer Simulator
Proof:
  
      
      Given
      
    
    
      
  
  
| 1 | instruction #6 is addi dst=2 src=3 imm=0 | 
|---|---|
| 2 | the PC at time 18 = 6 | 
| # | Claim | Reason | 
|---|---|---|
| 1 | the PC at time (18 + 1) = 6 + 1 | if instruction #6 is addi dst=2 src=3 imm=0and the PC at time 18 = 6, then the PC at time (18 + 1) = 6 + 1 | 
| 2 | 18 + 1 = 19 | 18 + 1 = 19 | 
| 3 | 6 + 1 = 7 | 6 + 1 = 7 | 
| 4 | the PC at time (18 + 1) = the PC at time 19 | if 18 + 1 = 19, then the PC at time (18 + 1) = the PC at time 19 | 
| 5 | the PC at time 19 = 7 | if the PC at time (18 + 1) = 6 + 1 and the PC at time (18 + 1) = the PC at time 19 and 6 + 1 = 7, then the PC at time 19 = 7 | 
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