Proof: Byte 3 Stays the Same 8

Let's prove the following theorem:

if the following are true:
  • instruction #4 is addi dst=4 src=4 imm=1
  • the PC at time 8 = 4
  • value of cell 3 at time 8 = 3

then value of cell 3 at time 9 = 3

Proof:

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Given
1 instruction #4 is addi dst=4 src=4 imm=1
2 the PC at time 8 = 4
3 value of cell 3 at time 8 = 3
Proof Table
# Claim Reason
1 not (3 = 4) not (3 = 4)
2 value of cell 3 at time (8 + 1) = value of cell 3 at time 8 if instruction #4 is addi dst=4 src=4 imm=1 and the PC at time 8 = 4 and not (3 = 4), then value of cell 3 at time (8 + 1) = value of cell 3 at time 8
3 8 + 1 = 9 8 + 1 = 9
4 value of cell 3 at time (8 + 1) = value of cell 3 at time 9 if 8 + 1 = 9, then value of cell 3 at time (8 + 1) = value of cell 3 at time 9
5 value of cell 3 at time 9 = value of cell 3 at time 8 if value of cell 3 at time (8 + 1) = value of cell 3 at time 9 and value of cell 3 at time (8 + 1) = value of cell 3 at time 8, then value of cell 3 at time 9 = value of cell 3 at time 8
6 value of cell 3 at time 9 = 3 if value of cell 3 at time 9 = value of cell 3 at time 8 and value of cell 3 at time 8 = 3, then value of cell 3 at time 9 = 3

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