Proof: Byte 4 Stays the Same 9
Let's prove the following theorem:
if the following are true:
- instruction #5 is
beq left=3 right=4 imm=1
- the PC at time 9 = 5
- value of cell 4 at time 9 = 2
then value of cell 4 at time 10 = 2
Proof:
Given
1 | instruction #5 is beq left=3 right=4 imm=1 |
---|---|
2 | the PC at time 9 = 5 |
3 | value of cell 4 at time 9 = 2 |
# | Claim | Reason |
---|---|---|
1 | value of cell 4 at time (9 + 1) = value of cell 4 at time 9 | if instruction #5 is beq left=3 right=4 imm=1 and the PC at time 9 = 5, then value of cell 4 at time (9 + 1) = value of cell 4 at time 9 |
2 | 9 + 1 = 10 | 9 + 1 = 10 |
3 | value of cell 4 at time (9 + 1) = value of cell 4 at time 10 | if 9 + 1 = 10, then value of cell 4 at time (9 + 1) = value of cell 4 at time 10 |
4 | value of cell 4 at time 10 = value of cell 4 at time 9 | if value of cell 4 at time (9 + 1) = value of cell 4 at time 10 and value of cell 4 at time (9 + 1) = value of cell 4 at time 9, then value of cell 4 at time 10 = value of cell 4 at time 9 |
5 | value of cell 4 at time 10 = 2 | if value of cell 4 at time 10 = value of cell 4 at time 9 and value of cell 4 at time 9 = 2, then value of cell 4 at time 10 = 2 |
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