Proof: Byte 8 Stays the Same 2

Let's prove the following theorem:

if the following are true:

instruction #2 is load dst=9 addr=6 imm=2
the PC at time 2 = 2
value of cell 8 at time 2 = 11

then value of cell 8 at time 3 = 11

Proof:

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Given

1	instruction #2 is `load dst=9 addr=6 imm=2`
2	the PC at time 2 = 2
3	value of cell 8 at time 2 = 11

Proof Table

#	Claim	Reason
1	not (8 = 9)	not (8 = 9) (Fixed Value Statement)
2	value of cell 8 at time (2 + 1) = value of cell 8 at time 2	if instruction #2 is `load dst=9 addr=6 imm=2` and the PC at time 2 = 2 and not (8 = 9), then value of cell 8 at time (2 + 1) = value of cell 8 at time 2 (LOAD Instruction Property 2)
3	2 + 1 = 3	2 + 1 = 3 (Fixed Value Statement)
4	value of cell 8 at time (2 + 1) = value of cell 8 at time 3	if 2 + 1 = 3, then value of cell 8 at time (2 + 1) = value of cell 8 at time 3 (Substitution)
5	value of cell 8 at time 3 = value of cell 8 at time 2	if value of cell 8 at time (2 + 1) = value of cell 8 at time 3 and value of cell 8 at time (2 + 1) = value of cell 8 at time 2, then value of cell 8 at time 3 = value of cell 8 at time 2 (Transitive Property of Equality Variation 2)
6	value of cell 8 at time 3 = 11	if value of cell 8 at time 3 = value of cell 8 at time 2 and value of cell 8 at time 2 = 11, then value of cell 8 at time 3 = 11 (Transitive Property of Equality)

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