Proof: Addi Insn 3
Let's prove the following theorem:
if the following are true:
- instruction #3 is
addi dst=6 src=6 imm=1
- the PC at time 3 = 3
- value of cell 6 at time 3 = 12
then value of cell 6 at time 4 = 13
Proof:
Given
1 | instruction #3 is addi dst=6 src=6 imm=1 |
---|---|
2 | the PC at time 3 = 3 |
3 | value of cell 6 at time 3 = 12 |
# | Claim | Reason |
---|---|---|
1 | value of cell 6 at time (3 + 1) = (value of cell 6 at time 3) + 1 | if instruction #3 is addi dst=6 src=6 imm=1 and the PC at time 3 = 3, then value of cell 6 at time (3 + 1) = (value of cell 6 at time 3) + 1 |
2 | 3 + 1 = 4 | 3 + 1 = 4 |
3 | value of cell 6 at time (3 + 1) = value of cell 6 at time 4 | if 3 + 1 = 4, then value of cell 6 at time (3 + 1) = value of cell 6 at time 4 |
4 | value of cell 6 at time 4 = (value of cell 6 at time 3) + 1 | if value of cell 6 at time (3 + 1) = value of cell 6 at time 4 and value of cell 6 at time (3 + 1) = (value of cell 6 at time 3) + 1, then value of cell 6 at time 4 = (value of cell 6 at time 3) + 1 |
5 | value of cell 6 at time 4 = 12 + 1 | if value of cell 6 at time 4 = (value of cell 6 at time 3) + 1 and value of cell 6 at time 3 = 12, then value of cell 6 at time 4 = 12 + 1 |
6 | 12 + 1 = 13 | 12 + 1 = 13 |
7 | value of cell 6 at time 4 = 13 | if value of cell 6 at time 4 = 12 + 1 and 12 + 1 = 13, then value of cell 6 at time 4 = 13 |
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