Proof: Pc 1
Let's prove the following theorem:
if the following are true:
- instruction #1 is
store src=7 addr=6 imm=0
- the PC at time 1 = 1
then the PC at time 2 = 2
Proof:
Given
1 | instruction #1 is store src=7 addr=6 imm=0 |
---|---|
2 | the PC at time 1 = 1 |
# | Claim | Reason |
---|---|---|
1 | the PC at time (1 + 1) = 1 + 1 | if instruction #1 is store src=7 addr=6 imm=0 and the PC at time 1 = 1, then the PC at time (1 + 1) = 1 + 1 |
2 | 1 + 1 = 2 | 1 + 1 = 2 |
3 | the PC at time (1 + 1) = the PC at time 2 | if 1 + 1 = 2, then the PC at time (1 + 1) = the PC at time 2 |
4 | the PC at time 2 = 2 | if the PC at time (1 + 1) = 1 + 1 and the PC at time (1 + 1) = the PC at time 2 and 1 + 1 = 2, then the PC at time 2 = 2 |
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