Proof: Pc 14

Let's prove the following theorem:

if the following are true:
  • instruction #0 is load dst=7 addr=5 imm=0
  • the PC at time 14 = 0

then the PC at time 15 = 1

Proof:

View as a tree | View dependent proofs | Try proving it

Given
1 instruction #0 is load dst=7 addr=5 imm=0
2 the PC at time 14 = 0
Proof Table
# Claim Reason
1 the PC at time (14 + 1) = 0 + 1 if instruction #0 is load dst=7 addr=5 imm=0 and the PC at time 14 = 0, then the PC at time (14 + 1) = 0 + 1
2 14 + 1 = 15 14 + 1 = 15
3 0 + 1 = 1 0 + 1 = 1
4 the PC at time (14 + 1) = the PC at time 15 if 14 + 1 = 15, then the PC at time (14 + 1) = the PC at time 15
5 the PC at time 15 = 1 if the PC at time (14 + 1) = 0 + 1 and the PC at time (14 + 1) = the PC at time 15 and 0 + 1 = 1, then the PC at time 15 = 1

Comments

Please log in to add comments