Proof: Do Tab At Unchanged 66
Let's prove the following theorem:
if the following are true:
- expression state at time 66 = "iterate_args"
- the tab at time 66 = 2
then the tab at time 67 = 2
Proof:
Given
1 | expression state at time 66 = "iterate_args" |
---|---|
2 | the tab at time 66 = 2 |
# | Claim | Reason |
---|---|---|
1 | the tab at time (66 + 1) = the tab at time 66 | if expression state at time 66 = "iterate_args", then the tab at time (66 + 1) = the tab at time 66 |
2 | the tab at time (66 + 1) = 2 | if the tab at time (66 + 1) = the tab at time 66 and the tab at time 66 = 2, then the tab at time (66 + 1) = 2 |
3 | 66 + 1 = 67 | 66 + 1 = 67 |
4 | the tab at time (66 + 1) = the tab at time 67 | if 66 + 1 = 67, then the tab at time (66 + 1) = the tab at time 67 |
5 | the tab at time 67 = 2 | if the tab at time (66 + 1) = the tab at time 67 and the tab at time (66 + 1) = 2, then the tab at time 67 = 2 |
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