Proof: Do Tab At Unchanged 67

Let's prove the following theorem:

if the following are true:

expression state at time 67 = "call_function_begin"
the tab at time 67 = 2

then the tab at time 68 = 2

Proof:

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Given

1	expression state at time 67 = "call_function_begin"
2	the tab at time 67 = 2

Proof Table

#	Claim	Reason
1	the tab at time (67 + 1) = the tab at time 67	if expression state at time 67 = "call_function_begin", then the tab at time (67 + 1) = the tab at time 67 (Assign Parent (7))
2	the tab at time (67 + 1) = 2	if the tab at time (67 + 1) = the tab at time 67 and the tab at time 67 = 2, then the tab at time (67 + 1) = 2 (Transitive Property of Equality)
3	67 + 1 = 68	67 + 1 = 68 (Fixed Value Statement)
4	the tab at time (67 + 1) = the tab at time 68	if 67 + 1 = 68, then the tab at time (67 + 1) = the tab at time 68 (Substitution)
5	the tab at time 68 = 2	if the tab at time (67 + 1) = the tab at time 68 and the tab at time (67 + 1) = 2, then the tab at time 68 = 2 (Transitive Property of Equality Variation 2)

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