Proof: Do Tab At Unchanged 68

Let's prove the following theorem:

if the following are true:

expression state at time 68 = "return"
the tab at time 68 = 2

then the tab at time 69 = 2

Proof:

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Given

1	expression state at time 68 = "return"
2	the tab at time 68 = 2

Proof Table

#	Claim	Reason
1	the tab at time (68 + 1) = the tab at time 68	if expression state at time 68 = "return", then the tab at time (68 + 1) = the tab at time 68 (Return (7))
2	the tab at time (68 + 1) = 2	if the tab at time (68 + 1) = the tab at time 68 and the tab at time 68 = 2, then the tab at time (68 + 1) = 2 (Transitive Property of Equality)
3	68 + 1 = 69	68 + 1 = 69 (Fixed Value Statement)
4	the tab at time (68 + 1) = the tab at time 69	if 68 + 1 = 69, then the tab at time (68 + 1) = the tab at time 69 (Substitution)
5	the tab at time 69 = 2	if the tab at time (68 + 1) = the tab at time 69 and the tab at time (68 + 1) = 2, then the tab at time 69 = 2 (Transitive Property of Equality Variation 2)

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