Proof: Do Tab At Unchanged 71

Let's prove the following theorem:

if the following are true:

expression state at time 71 = "return"
the tab at time 71 = 2

then the tab at time 72 = 2

Proof:

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Given

1	expression state at time 71 = "return"
2	the tab at time 71 = 2

Proof Table

#	Claim	Reason
1	the tab at time (71 + 1) = the tab at time 71	if expression state at time 71 = "return", then the tab at time (71 + 1) = the tab at time 71 (Return (7))
2	the tab at time (71 + 1) = 2	if the tab at time (71 + 1) = the tab at time 71 and the tab at time 71 = 2, then the tab at time (71 + 1) = 2 (Transitive Property of Equality)
3	71 + 1 = 72	71 + 1 = 72 (Fixed Value Statement)
4	the tab at time (71 + 1) = the tab at time 72	if 71 + 1 = 72, then the tab at time (71 + 1) = the tab at time 72 (Substitution)
5	the tab at time 72 = 2	if the tab at time (71 + 1) = the tab at time 72 and the tab at time (71 + 1) = 2, then the tab at time 72 = 2 (Transitive Property of Equality Variation 2)

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