Proof: Get Begin Expr Params 62

Let's prove the following theorem:

if the following are true:

expression state at time 62 = "begin_expr"
the expression at time 62 = self.age
arguments stack at time 62 = [ [ 12, [ ] ], [ ] ]

then arguments stack at time 63 = [ [ self, [ ] ], [ [ 12, [ ] ], [ ] ] ]

Proof:

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Given

1	expression state at time 62 = "begin_expr"
2	the expression at time 62 = `self.age`
3	arguments stack at time 62 = [ [ 12, [ ] ], [ ] ]

Proof Table

#	Claim	Reason
1	arguments stack at time (62 + 1) = [ [ self, [ ] ], arguments stack at time 62 ]	if expression state at time 62 = "begin_expr" and the expression at time 62 = `self.age`, then arguments stack at time (62 + 1) = [ [ self, [ ] ], arguments stack at time 62 ] (Begin Get Attribute (3))
2	[ [ self, [ ] ], arguments stack at time 62 ] = [ [ self, [ ] ], [ [ 12, [ ] ], [ ] ] ]	if arguments stack at time 62 = [ [ 12, [ ] ], [ ] ], then [ [ self, [ ] ], arguments stack at time 62 ] = [ [ self, [ ] ], [ [ 12, [ ] ], [ ] ] ] (Substitution)
3	arguments stack at time (62 + 1) = [ [ self, [ ] ], [ [ 12, [ ] ], [ ] ] ]	if arguments stack at time (62 + 1) = [ [ self, [ ] ], arguments stack at time 62 ] and [ [ self, [ ] ], arguments stack at time 62 ] = [ [ self, [ ] ], [ [ 12, [ ] ], [ ] ] ], then arguments stack at time (62 + 1) = [ [ self, [ ] ], [ [ 12, [ ] ], [ ] ] ] (Transitive Property of Equality)
4	62 + 1 = 63	62 + 1 = 63 (Fixed Value Statement)
5	arguments stack at time (62 + 1) = arguments stack at time 63	if 62 + 1 = 63, then arguments stack at time (62 + 1) = arguments stack at time 63 (Substitution)
6	arguments stack at time 63 = [ [ self, [ ] ], [ [ 12, [ ] ], [ ] ] ]	if arguments stack at time (62 + 1) = arguments stack at time 63 and arguments stack at time (62 + 1) = [ [ self, [ ] ], [ [ 12, [ ] ], [ ] ] ], then arguments stack at time 63 = [ [ self, [ ] ], [ [ 12, [ ] ], [ ] ] ] (Transitive Property of Equality Variation 2)

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