Proof: Get Begin Expr Parent 62

Let's prove the following theorem:

if the following are true:
  • expression state at time 62 = "begin_expr"
  • the expression at time 62 = self.age
  • parent stack at time 62 = [ __mul__(self.age, 12), [ ] ]

then parent stack at time 63 = [ self.age, [ __mul__(self.age, 12), [ ] ] ]

Proof:

View as a tree | View dependent proofs | Try proving it

Given
1 expression state at time 62 = "begin_expr"
2 the expression at time 62 = self.age
3 parent stack at time 62 = [ __mul__(self.age, 12), [ ] ]
Proof Table
# Claim Reason
1 parent stack at time (62 + 1) = [ self.age, parent stack at time 62 ] if expression state at time 62 = "begin_expr" and the expression at time 62 = self.age, then parent stack at time (62 + 1) = [ self.age, parent stack at time 62 ]
2 [ self.age, parent stack at time 62 ] = [ self.age, [ __mul__(self.age, 12), [ ] ] ] if parent stack at time 62 = [ __mul__(self.age, 12), [ ] ], then [ self.age, parent stack at time 62 ] = [ self.age, [ __mul__(self.age, 12), [ ] ] ]
3 parent stack at time (62 + 1) = [ self.age, [ __mul__(self.age, 12), [ ] ] ] if parent stack at time (62 + 1) = [ self.age, parent stack at time 62 ] and [ self.age, parent stack at time 62 ] = [ self.age, [ __mul__(self.age, 12), [ ] ] ], then parent stack at time (62 + 1) = [ self.age, [ __mul__(self.age, 12), [ ] ] ]
4 62 + 1 = 63 62 + 1 = 63
5 parent stack at time (62 + 1) = parent stack at time 63 if 62 + 1 = 63, then parent stack at time (62 + 1) = parent stack at time 63
6 parent stack at time 63 = [ self.age, [ __mul__(self.age, 12), [ ] ] ] if parent stack at time (62 + 1) = parent stack at time 63 and parent stack at time (62 + 1) = [ self.age, [ __mul__(self.age, 12), [ ] ] ], then parent stack at time 63 = [ self.age, [ __mul__(self.age, 12), [ ] ] ]

Comments

Please log in to add comments