Proof: Do Expr At Unchanged 14

Let's prove the following theorem:

if the following are true:

expression state at time 14 = "call_function_begin"
the expression at time 14 = Dog()

then the expression at time 15 = Dog()

Proof:

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Given

1	expression state at time 14 = "call_function_begin"
2	the expression at time 14 = `Dog()`

Proof Table

#	Claim	Reason
1	the expression at time (14 + 1) = the expression at time 14	if expression state at time 14 = "call_function_begin", then the expression at time (14 + 1) = the expression at time 14 (Assign Parent (3))
2	the expression at time (14 + 1) = `Dog()`	if the expression at time (14 + 1) = the expression at time 14 and the expression at time 14 = `Dog()`, then the expression at time (14 + 1) = `Dog()` (Transitive Property of Equality)
3	14 + 1 = 15	14 + 1 = 15 (Fixed Value Statement)
4	the expression at time (14 + 1) = the expression at time 15	if 14 + 1 = 15, then the expression at time (14 + 1) = the expression at time 15 (Substitution)
5	the expression at time 15 = `Dog()`	if the expression at time (14 + 1) = the expression at time 15 and the expression at time (14 + 1) = `Dog()`, then the expression at time 15 = `Dog()` (Transitive Property of Equality Variation 2)

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