Proof: Do Stack At Unchanged 37
Let's prove the following theorem:
if the following are true:
- expression state at time 37 = "begin_expr"
- stack at time 37 = [ ]
then stack at time 38 = [ ]
Proof:
Given
1 | expression state at time 37 = "begin_expr" |
---|---|
2 | stack at time 37 = [ ] |
# | Claim | Reason |
---|---|---|
1 | stack at time (37 + 1) = stack at time 37 | if expression state at time 37 = "begin_expr", then stack at time (37 + 1) = stack at time 37 |
2 | stack at time (37 + 1) = [ ] | if stack at time (37 + 1) = stack at time 37 and stack at time 37 = [ ], then stack at time (37 + 1) = [ ] |
3 | 37 + 1 = 38 | 37 + 1 = 38 |
4 | stack at time (37 + 1) = stack at time 38 | if 37 + 1 = 38, then stack at time (37 + 1) = stack at time 38 |
5 | stack at time 38 = [ ] | if stack at time (37 + 1) = stack at time 38 and stack at time (37 + 1) = [ ], then stack at time 38 = [ ] |
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