Proof: Do Stack At Unchanged 39

Let's prove the following theorem:

if the following are true:

expression state at time 39 = "call_function_begin"
stack at time 39 = [ ]

then stack at time 40 = [ ]

Proof:

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Given

1	expression state at time 39 = "call_function_begin"
2	stack at time 39 = [ ]

Proof Table

#	Claim	Reason
1	stack at time (39 + 1) = stack at time 39	if expression state at time 39 = "call_function_begin", then stack at time (39 + 1) = stack at time 39 (Assign Parent (8))
2	stack at time (39 + 1) = [ ]	if stack at time (39 + 1) = stack at time 39 and stack at time 39 = [ ], then stack at time (39 + 1) = [ ] (Transitive Property of Equality)
3	39 + 1 = 40	39 + 1 = 40 (Fixed Value Statement)
4	stack at time (39 + 1) = stack at time 40	if 39 + 1 = 40, then stack at time (39 + 1) = stack at time 40 (Substitution)
5	stack at time 40 = [ ]	if stack at time (39 + 1) = stack at time 40 and stack at time (39 + 1) = [ ], then stack at time 40 = [ ] (Transitive Property of Equality Variation 2)

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