Proof: Do Tab At Unchanged 34

Let's prove the following theorem:

if the following are true:

expression state at time 34 = "call_returned"
the tab at time 34 = 0

then the tab at time 35 = 0

Proof:

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Given

1	expression state at time 34 = "call_returned"
2	the tab at time 34 = 0

Proof Table

#	Claim	Reason
1	the tab at time (34 + 1) = the tab at time 34	if expression state at time 34 = "call_returned", then the tab at time (34 + 1) = the tab at time 34 (Call Returned Unchanged (3))
2	the tab at time (34 + 1) = 0	if the tab at time (34 + 1) = the tab at time 34 and the tab at time 34 = 0, then the tab at time (34 + 1) = 0 (Transitive Property of Equality)
3	34 + 1 = 35	34 + 1 = 35 (Fixed Value Statement)
4	the tab at time (34 + 1) = the tab at time 35	if 34 + 1 = 35, then the tab at time (34 + 1) = the tab at time 35 (Substitution)
5	the tab at time 35 = 0	if the tab at time (34 + 1) = the tab at time 35 and the tab at time (34 + 1) = 0, then the tab at time 35 = 0 (Transitive Property of Equality Variation 2)

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