Proof: Do Tab At Unchanged 52
Let's prove the following theorem:
if the following are true:
- expression state at time 52 = "call_function_begin"
- the tab at time 52 = 2
then the tab at time 53 = 2
Proof:
Given
1 | expression state at time 52 = "call_function_begin" |
---|---|
2 | the tab at time 52 = 2 |
# | Claim | Reason |
---|---|---|
1 | the tab at time (52 + 1) = the tab at time 52 | if expression state at time 52 = "call_function_begin", then the tab at time (52 + 1) = the tab at time 52 |
2 | the tab at time (52 + 1) = 2 | if the tab at time (52 + 1) = the tab at time 52 and the tab at time 52 = 2, then the tab at time (52 + 1) = 2 |
3 | 52 + 1 = 53 | 52 + 1 = 53 |
4 | the tab at time (52 + 1) = the tab at time 53 | if 52 + 1 = 53, then the tab at time (52 + 1) = the tab at time 53 |
5 | the tab at time 53 = 2 | if the tab at time (52 + 1) = the tab at time 53 and the tab at time (52 + 1) = 2, then the tab at time 53 = 2 |
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