Proof: Do Tab At Unchanged 58

Let's prove the following theorem:

if the following are true:

expression state at time 58 = "call_function_begin"
the tab at time 58 = 2

then the tab at time 59 = 2

Proof:

View as a tree | View dependent proofs | Try proving it

Given

1	expression state at time 58 = "call_function_begin"
2	the tab at time 58 = 2

Proof Table

#	Claim	Reason
1	the tab at time (58 + 1) = the tab at time 58	if expression state at time 58 = "call_function_begin", then the tab at time (58 + 1) = the tab at time 58 (Assign Parent (7))
2	the tab at time (58 + 1) = 2	if the tab at time (58 + 1) = the tab at time 58 and the tab at time 58 = 2, then the tab at time (58 + 1) = 2 (Transitive Property of Equality)
3	58 + 1 = 59	58 + 1 = 59 (Fixed Value Statement)
4	the tab at time (58 + 1) = the tab at time 59	if 58 + 1 = 59, then the tab at time (58 + 1) = the tab at time 59 (Substitution)
5	the tab at time 59 = 2	if the tab at time (58 + 1) = the tab at time 59 and the tab at time (58 + 1) = 2, then the tab at time 59 = 2 (Transitive Property of Equality Variation 2)

Comments

Please log in to add comments