Proof: Do Tab At Unchanged 64

Let's prove the following theorem:

if the following are true:

expression state at time 64 = "call_returned"
the tab at time 64 = 0

then the tab at time 65 = 0

Proof:

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Given

1	expression state at time 64 = "call_returned"
2	the tab at time 64 = 0

Proof Table

#	Claim	Reason
1	the tab at time (64 + 1) = the tab at time 64	if expression state at time 64 = "call_returned", then the tab at time (64 + 1) = the tab at time 64 (Call Returned Unchanged (3))
2	the tab at time (64 + 1) = 0	if the tab at time (64 + 1) = the tab at time 64 and the tab at time 64 = 0, then the tab at time (64 + 1) = 0 (Transitive Property of Equality)
3	64 + 1 = 65	64 + 1 = 65 (Fixed Value Statement)
4	the tab at time (64 + 1) = the tab at time 65	if 64 + 1 = 65, then the tab at time (64 + 1) = the tab at time 65 (Substitution)
5	the tab at time 65 = 0	if the tab at time (64 + 1) = the tab at time 65 and the tab at time (64 + 1) = 0, then the tab at time 65 = 0 (Transitive Property of Equality Variation 2)

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