Proof: Do Tab At Unchanged 69

Let's prove the following theorem:

if the following are true:

expression state at time 69 = "call_function_begin"
the tab at time 69 = 0

then the tab at time 70 = 0

Proof:

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Given

1	expression state at time 69 = "call_function_begin"
2	the tab at time 69 = 0

Proof Table

#	Claim	Reason
1	the tab at time (69 + 1) = the tab at time 69	if expression state at time 69 = "call_function_begin", then the tab at time (69 + 1) = the tab at time 69 (Assign Parent (7))
2	the tab at time (69 + 1) = 0	if the tab at time (69 + 1) = the tab at time 69 and the tab at time 69 = 0, then the tab at time (69 + 1) = 0 (Transitive Property of Equality)
3	69 + 1 = 70	69 + 1 = 70 (Fixed Value Statement)
4	the tab at time (69 + 1) = the tab at time 70	if 69 + 1 = 70, then the tab at time (69 + 1) = the tab at time 70 (Substitution)
5	the tab at time 70 = 0	if the tab at time (69 + 1) = the tab at time 70 and the tab at time (69 + 1) = 0, then the tab at time 70 = 0 (Transitive Property of Equality Variation 2)

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