Proof: Do Tab At Unchanged 77
Let's prove the following theorem:
if the following are true:
- expression state at time 77 = "iterate_args"
- the tab at time 77 = 2
then the tab at time 78 = 2
Proof:
Given
1 | expression state at time 77 = "iterate_args" |
---|---|
2 | the tab at time 77 = 2 |
# | Claim | Reason |
---|---|---|
1 | the tab at time (77 + 1) = the tab at time 77 | if expression state at time 77 = "iterate_args", then the tab at time (77 + 1) = the tab at time 77 |
2 | the tab at time (77 + 1) = 2 | if the tab at time (77 + 1) = the tab at time 77 and the tab at time 77 = 2, then the tab at time (77 + 1) = 2 |
3 | 77 + 1 = 78 | 77 + 1 = 78 |
4 | the tab at time (77 + 1) = the tab at time 78 | if 77 + 1 = 78, then the tab at time (77 + 1) = the tab at time 78 |
5 | the tab at time 78 = 2 | if the tab at time (77 + 1) = the tab at time 78 and the tab at time (77 + 1) = 2, then the tab at time 78 = 2 |
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