Proof: Get Begin Expr Params 43

Let's prove the following theorem:

if the following are true:
  • expression state at time 43 = "begin_expr"
  • the expression at time 43 = self."x" = __add__(self.x, 5)
  • arguments stack at time 43 = [ ]

then arguments stack at time 44 = [ [ __add__(self.x, 5), [ ] ], [ ] ]

Proof:

View as a tree | View dependent proofs | Try proving it

Given
1 expression state at time 43 = "begin_expr"
2 the expression at time 43 = self."x" = __add__(self.x, 5)
3 arguments stack at time 43 = [ ]
Proof Table
# Claim Reason
1 arguments stack at time (43 + 1) = [ [ __add__(self.x, 5), [ ] ], arguments stack at time 43 ] if expression state at time 43 = "begin_expr" and the expression at time 43 = self."x" = __add__(self.x, 5), then arguments stack at time (43 + 1) = [ [ __add__(self.x, 5), [ ] ], arguments stack at time 43 ]
2 [ [ __add__(self.x, 5), [ ] ], arguments stack at time 43 ] = [ [ __add__(self.x, 5), [ ] ], [ ] ] if arguments stack at time 43 = [ ], then [ [ __add__(self.x, 5), [ ] ], arguments stack at time 43 ] = [ [ __add__(self.x, 5), [ ] ], [ ] ]
3 arguments stack at time (43 + 1) = [ [ __add__(self.x, 5), [ ] ], [ ] ] if arguments stack at time (43 + 1) = [ [ __add__(self.x, 5), [ ] ], arguments stack at time 43 ] and [ [ __add__(self.x, 5), [ ] ], arguments stack at time 43 ] = [ [ __add__(self.x, 5), [ ] ], [ ] ], then arguments stack at time (43 + 1) = [ [ __add__(self.x, 5), [ ] ], [ ] ]
4 43 + 1 = 44 43 + 1 = 44
5 arguments stack at time (43 + 1) = arguments stack at time 44 if 43 + 1 = 44, then arguments stack at time (43 + 1) = arguments stack at time 44
6 arguments stack at time 44 = [ [ __add__(self.x, 5), [ ] ], [ ] ] if arguments stack at time (43 + 1) = arguments stack at time 44 and arguments stack at time (43 + 1) = [ [ __add__(self.x, 5), [ ] ], [ ] ], then arguments stack at time 44 = [ [ __add__(self.x, 5), [ ] ], [ ] ]

Comments

Please log in to add comments