Proof: Get Begin Expr Params Unchanged75
Let's prove the following theorem:
if the following are true:
- the expression at time 75 = 5
- expression state at time 75 = "begin_expr"
- 5 is constant
- arguments stack at time 75 = [ [ ], [ ] ]
then arguments stack at time 76 = [ [ ], [ ] ]
Proof:
Given
1 | the expression at time 75 = 5 |
---|---|
2 | expression state at time 75 = "begin_expr" |
3 | 5 is constant |
4 | arguments stack at time 75 = [ [ ], [ ] ] |
# | Claim | Reason |
---|---|---|
1 | arguments stack at time (75 + 1) = arguments stack at time 75 | if expression state at time 75 = "begin_expr" and the expression at time 75 = 5 and 5 is constant, then arguments stack at time (75 + 1) = arguments stack at time 75 |
2 | arguments stack at time (75 + 1) = [ [ ], [ ] ] | if arguments stack at time (75 + 1) = arguments stack at time 75 and arguments stack at time 75 = [ [ ], [ ] ], then arguments stack at time (75 + 1) = [ [ ], [ ] ] |
3 | 75 + 1 = 76 | 75 + 1 = 76 |
4 | arguments stack at time (75 + 1) = arguments stack at time 76 | if 75 + 1 = 76, then arguments stack at time (75 + 1) = arguments stack at time 76 |
5 | arguments stack at time 76 = [ [ ], [ ] ] | if arguments stack at time (75 + 1) = arguments stack at time 76 and arguments stack at time (75 + 1) = [ [ ], [ ] ], then arguments stack at time 76 = [ [ ], [ ] ] |
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