Proof: Get Iterate End Expr 68

Let's prove the following theorem:

if the following are true:

expression state at time 68 = "iterate_args"
arguments stack at time 68 = [ [ ], [ ] ]
parent stack at time 68 = [ joe.jump(), [ ] ]

then the expression at time 69 = joe.jump()

Proof:

View as a tree | View dependent proofs | Try proving it

Given

1	expression state at time 68 = "iterate_args"
2	arguments stack at time 68 = [ [ ], [ ] ]
3	parent stack at time 68 = [ `joe.jump()`, [ ] ]

Proof Table

#	Claim	Reason
1	the expression at time (68 + 1) = `joe.jump()`	if expression state at time 68 = "iterate_args" and arguments stack at time 68 = [ [ ], [ ] ] and parent stack at time 68 = [ `joe.jump()`, [ ] ], then the expression at time (68 + 1) = `joe.jump()` (Iterate Arguments Finished Rule)
2	68 + 1 = 69	68 + 1 = 69 (Fixed Value Statement)
3	the expression at time (68 + 1) = the expression at time 69	if 68 + 1 = 69, then the expression at time (68 + 1) = the expression at time 69 (Substitution)
4	the expression at time 69 = `joe.jump()`	if the expression at time (68 + 1) = the expression at time 69 and the expression at time (68 + 1) = `joe.jump()`, then the expression at time 69 = `joe.jump()` (Transitive Property of Equality Variation 2)

Comments

Please log in to add comments