Proof: Get Iterate End Params 13

Let's prove the following theorem:

if the following are true:

expression state at time 13 = "iterate_args"
arguments stack at time 13 = [ [ ], [ ] ]
parent stack at time 13 = [ Dog(), [ ] ]

then arguments stack at time 14 = [ ]

Proof:

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Given

1	expression state at time 13 = "iterate_args"
2	arguments stack at time 13 = [ [ ], [ ] ]
3	parent stack at time 13 = [ `Dog()`, [ ] ]

Proof Table

#	Claim	Reason
1	arguments stack at time (13 + 1) = [ ]	if expression state at time 13 = "iterate_args" and arguments stack at time 13 = [ [ ], [ ] ] and parent stack at time 13 = [ `Dog()`, [ ] ], then arguments stack at time (13 + 1) = [ ] (Iterate Args Empty (4))
2	13 + 1 = 14	13 + 1 = 14 (Fixed Value Statement)
3	arguments stack at time (13 + 1) = arguments stack at time 14	if 13 + 1 = 14, then arguments stack at time (13 + 1) = arguments stack at time 14 (Substitution)
4	arguments stack at time 14 = [ ]	if arguments stack at time (13 + 1) = arguments stack at time 14 and arguments stack at time (13 + 1) = [ ], then arguments stack at time 14 = [ ] (Transitive Property of Equality Variation 2)

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