Proof: Get Iterate End State 68

Let's prove the following theorem:

if the following are true:

expression state at time 68 = "iterate_args"
arguments stack at time 68 = [ [ ], [ ] ]
parent stack at time 68 = [ joe.jump(), [ ] ]

then expression state at time 69 = "call_function_begin"

Proof:

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Given

1	expression state at time 68 = "iterate_args"
2	arguments stack at time 68 = [ [ ], [ ] ]
3	parent stack at time 68 = [ `joe.jump()`, [ ] ]

Proof Table

#	Claim	Reason
1	expression state at time (68 + 1) = "call_function_begin"	if expression state at time 68 = "iterate_args" and arguments stack at time 68 = [ [ ], [ ] ] and parent stack at time 68 = [ `joe.jump()`, [ ] ], then expression state at time (68 + 1) = "call_function_begin" (Iterate Arguments Finished State Rule)
2	68 + 1 = 69	68 + 1 = 69 (Fixed Value Statement)
3	expression state at time (68 + 1) = expression state at time 69	if 68 + 1 = 69, then expression state at time (68 + 1) = expression state at time 69 (Substitution)
4	expression state at time 69 = "call_function_begin"	if expression state at time (68 + 1) = expression state at time 69 and expression state at time (68 + 1) = "call_function_begin", then expression state at time 69 = "call_function_begin" (Transitive Property of Equality Variation 2)

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