Proof: Get Iterate Expr 19

Let's prove the following theorem:

if the following are true:

expression state at time 19 = "iterate_args"
arguments stack at time 19 = [ [ 0, [ ] ], [ ] ]

then the expression at time 20 = 0

Proof:

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Given

1	expression state at time 19 = "iterate_args"
2	arguments stack at time 19 = [ [ 0, [ ] ], [ ] ]

Proof Table

#	Claim	Reason
1	the expression at time (19 + 1) = 0	if expression state at time 19 = "iterate_args" and arguments stack at time 19 = [ [ 0, [ ] ], [ ] ], then the expression at time (19 + 1) = 0 (Iterate Arguments Expression Property)
2	19 + 1 = 20	19 + 1 = 20 (Fixed Value Statement)
3	the expression at time (19 + 1) = the expression at time 20	if 19 + 1 = 20, then the expression at time (19 + 1) = the expression at time 20 (Substitution)
4	the expression at time 20 = 0	if the expression at time (19 + 1) = the expression at time 20 and the expression at time (19 + 1) = 0, then the expression at time 20 = 0 (Transitive Property of Equality Variation 2)

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