Proof: Get Iterate Params 19

Let's prove the following theorem:

if the following are true:
  • expression state at time 19 = "iterate_args"
  • arguments stack at time 19 = [ [ 0, [ ] ], [ ] ]

then arguments stack at time 20 = [ [ ], [ ] ]

Proof:

View as a tree | View dependent proofs | Try proving it

Given
1 expression state at time 19 = "iterate_args"
2 arguments stack at time 19 = [ [ 0, [ ] ], [ ] ]
Proof Table
# Claim Reason
1 arguments stack at time (19 + 1) = [ [ ], [ ] ] if expression state at time 19 = "iterate_args" and arguments stack at time 19 = [ [ 0, [ ] ], [ ] ], then arguments stack at time (19 + 1) = [ [ ], [ ] ]
2 19 + 1 = 20 19 + 1 = 20
3 arguments stack at time (19 + 1) = arguments stack at time 20 if 19 + 1 = 20, then arguments stack at time (19 + 1) = arguments stack at time 20
4 arguments stack at time 20 = [ [ ], [ ] ] if arguments stack at time (19 + 1) = arguments stack at time 20 and arguments stack at time (19 + 1) = [ [ ], [ ] ], then arguments stack at time 20 = [ [ ], [ ] ]

Comments

Please log in to add comments