Proof: Get Iterate Parent 19

Let's prove the following theorem:

if the following are true:

expression state at time 19 = "iterate_args"
arguments stack at time 19 = [ [ 0, [ ] ], [ ] ]
parent stack at time 19 = [ self."x" = 0, [ ] ]

then parent stack at time 20 = [ self."x" = 0, [ ] ]

Proof:

View as a tree | View dependent proofs | Try proving it

Given

1	expression state at time 19 = "iterate_args"
2	arguments stack at time 19 = [ [ 0, [ ] ], [ ] ]
3	parent stack at time 19 = [ self."x" = 0, [ ] ]

Proof Table

#	Claim	Reason
1	parent stack at time (19 + 1) = parent stack at time 19	if expression state at time 19 = "iterate_args" and arguments stack at time 19 = [ [ 0, [ ] ], [ ] ], then parent stack at time (19 + 1) = parent stack at time 19 (Do Iterage Args (4))
2	parent stack at time (19 + 1) = [ self."x" = 0, [ ] ]	if parent stack at time (19 + 1) = parent stack at time 19 and parent stack at time 19 = [ self."x" = 0, [ ] ], then parent stack at time (19 + 1) = [ self."x" = 0, [ ] ] (Transitive Property of Equality)
3	19 + 1 = 20	19 + 1 = 20 (Fixed Value Statement)
4	parent stack at time (19 + 1) = parent stack at time 20	if 19 + 1 = 20, then parent stack at time (19 + 1) = parent stack at time 20 (Substitution)
5	parent stack at time 20 = [ self."x" = 0, [ ] ]	if parent stack at time (19 + 1) = parent stack at time 20 and parent stack at time (19 + 1) = [ self."x" = 0, [ ] ], then parent stack at time 20 = [ self."x" = 0, [ ] ] (Transitive Property of Equality Variation 2)

Comments

Please log in to add comments