Proof: Write Skip Line Tab 5
Let's prove the following theorem:
if the following are true:
- the line at time 5 = 6
- the tab at time 5 = 1
- statement at line 6, tab 2 =
self.x = self.x + 5
then the tab at time 6 = 1
Proof:
Given
1 | the line at time 5 = 6 |
---|---|
2 | the tab at time 5 = 1 |
3 | statement at line 6, tab 2 = self.x = self.x + 5 |
# | Claim | Reason |
---|---|---|
1 | 2 > 1 | 2 > 1 |
2 | the tab at time (5 + 1) = the tab at time 5 | if the line at time 5 = 6 and the tab at time 5 = 1 and statement at line 6, tab 2 = self.x = self.x + 5 and 2 > 1, then the tab at time (5 + 1) = the tab at time 5 |
3 | the tab at time (5 + 1) = 1 | if the tab at time (5 + 1) = the tab at time 5 and the tab at time 5 = 1, then the tab at time (5 + 1) = 1 |
4 | 5 + 1 = 6 | 5 + 1 = 6 |
5 | the tab at time (5 + 1) = the tab at time 6 | if 5 + 1 = 6, then the tab at time (5 + 1) = the tab at time 6 |
6 | the tab at time 6 = 1 | if the tab at time (5 + 1) = the tab at time 6 and the tab at time (5 + 1) = 1, then the tab at time 6 = 1 |
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