Proof: Do Stack At Unchanged 35
Let's prove the following theorem:
if the following are true:
- expression state at time 35 = "iterate_args"
- stack at time 35 = [ ]
then stack at time 36 = [ ]
Proof:
Given
1 | expression state at time 35 = "iterate_args" |
---|---|
2 | stack at time 35 = [ ] |
# | Claim | Reason |
---|---|---|
1 | stack at time (35 + 1) = stack at time 35 | if expression state at time 35 = "iterate_args", then stack at time (35 + 1) = stack at time 35 |
2 | stack at time (35 + 1) = [ ] | if stack at time (35 + 1) = stack at time 35 and stack at time 35 = [ ], then stack at time (35 + 1) = [ ] |
3 | 35 + 1 = 36 | 35 + 1 = 36 |
4 | stack at time (35 + 1) = stack at time 36 | if 35 + 1 = 36, then stack at time (35 + 1) = stack at time 36 |
5 | stack at time 36 = [ ] | if stack at time (35 + 1) = stack at time 36 and stack at time (35 + 1) = [ ], then stack at time 36 = [ ] |
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