Proof: Do Tab At Unchanged 2

Let's prove the following theorem:

if the following are true:

expression state at time 2 = "iterate_args"
the tab at time 2 = 0

then the tab at time 3 = 0

Proof:

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Given

1	expression state at time 2 = "iterate_args"
2	the tab at time 2 = 0

Proof Table

#	Claim	Reason
1	the tab at time (2 + 1) = the tab at time 2	if expression state at time 2 = "iterate_args", then the tab at time (2 + 1) = the tab at time 2 (Iterate Insn (4))
2	the tab at time (2 + 1) = 0	if the tab at time (2 + 1) = the tab at time 2 and the tab at time 2 = 0, then the tab at time (2 + 1) = 0 (Transitive Property of Equality)
3	2 + 1 = 3	2 + 1 = 3 (Fixed Value Statement)
4	the tab at time (2 + 1) = the tab at time 3	if 2 + 1 = 3, then the tab at time (2 + 1) = the tab at time 3 (Substitution)
5	the tab at time 3 = 0	if the tab at time (2 + 1) = the tab at time 3 and the tab at time (2 + 1) = 0, then the tab at time 3 = 0 (Transitive Property of Equality Variation 2)

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