Proof: Do Tab At Unchanged 3

Let's prove the following theorem:

if the following are true:
  • expression state at time 3 = "begin_expr"
  • the tab at time 3 = 0

then the tab at time 4 = 0

Proof:

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Given
1 expression state at time 3 = "begin_expr"
2 the tab at time 3 = 0
Proof Table
# Claim Reason
1 the tab at time (3 + 1) = the tab at time 3 if expression state at time 3 = "begin_expr", then the tab at time (3 + 1) = the tab at time 3
2 the tab at time (3 + 1) = 0 if the tab at time (3 + 1) = the tab at time 3 and the tab at time 3 = 0, then the tab at time (3 + 1) = 0
3 3 + 1 = 4 3 + 1 = 4
4 the tab at time (3 + 1) = the tab at time 4 if 3 + 1 = 4, then the tab at time (3 + 1) = the tab at time 4
5 the tab at time 4 = 0 if the tab at time (3 + 1) = the tab at time 4 and the tab at time (3 + 1) = 0, then the tab at time 4 = 0

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