Proof: Do Tab At Unchanged 5

Let's prove the following theorem:

if the following are true:

expression state at time 5 = "begin_expr"
the tab at time 5 = 0

then the tab at time 6 = 0

Proof:

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Given

1	expression state at time 5 = "begin_expr"
2	the tab at time 5 = 0

Proof Table

#	Claim	Reason
1	the tab at time (5 + 1) = the tab at time 5	if expression state at time 5 = "begin_expr", then the tab at time (5 + 1) = the tab at time 5 (Insn Count Begin Expression (4))
2	the tab at time (5 + 1) = 0	if the tab at time (5 + 1) = the tab at time 5 and the tab at time 5 = 0, then the tab at time (5 + 1) = 0 (Transitive Property of Equality)
3	5 + 1 = 6	5 + 1 = 6 (Fixed Value Statement)
4	the tab at time (5 + 1) = the tab at time 6	if 5 + 1 = 6, then the tab at time (5 + 1) = the tab at time 6 (Substitution)
5	the tab at time 6 = 0	if the tab at time (5 + 1) = the tab at time 6 and the tab at time (5 + 1) = 0, then the tab at time 6 = 0 (Transitive Property of Equality Variation 2)

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