Proof: Get Begin Expr Params Unchanged8
Let's prove the following theorem:
if the following are true:
- the expression at time 8 = "Estonia"
- expression state at time 8 = "begin_expr"
- "Estonia" is constant
- arguments stack at time 8 = [ [ ], [ [ entry "MX": "Mexico", [ ] ], [ ] ] ]
then arguments stack at time 9 = [ [ ], [ [ entry "MX": "Mexico", [ ] ], [ ] ] ]
Proof:
Given
1 | the expression at time 8 = "Estonia" |
---|---|
2 | expression state at time 8 = "begin_expr" |
3 | "Estonia" is constant |
4 | arguments stack at time 8 = [ [ ], [ [ entry "MX": "Mexico", [ ] ], [ ] ] ] |
# | Claim | Reason |
---|---|---|
1 | arguments stack at time (8 + 1) = arguments stack at time 8 | if expression state at time 8 = "begin_expr" and the expression at time 8 = "Estonia" and "Estonia" is constant, then arguments stack at time (8 + 1) = arguments stack at time 8 |
2 | arguments stack at time (8 + 1) = [ [ ], [ [ entry "MX": "Mexico", [ ] ], [ ] ] ] | if arguments stack at time (8 + 1) = arguments stack at time 8 and arguments stack at time 8 = [ [ ], [ [ entry "MX": "Mexico", [ ] ], [ ] ] ], then arguments stack at time (8 + 1) = [ [ ], [ [ entry "MX": "Mexico", [ ] ], [ ] ] ] |
3 | 8 + 1 = 9 | 8 + 1 = 9 |
4 | arguments stack at time (8 + 1) = arguments stack at time 9 | if 8 + 1 = 9, then arguments stack at time (8 + 1) = arguments stack at time 9 |
5 | arguments stack at time 9 = [ [ ], [ [ entry "MX": "Mexico", [ ] ], [ ] ] ] | if arguments stack at time (8 + 1) = arguments stack at time 9 and arguments stack at time (8 + 1) = [ [ ], [ [ entry "MX": "Mexico", [ ] ], [ ] ] ], then arguments stack at time 9 = [ [ ], [ [ entry "MX": "Mexico", [ ] ], [ ] ] ] |
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