Proof: Get Iterate End Expr 21

Let's prove the following theorem:

if the following are true:

expression state at time 21 = "iterate_args"
arguments stack at time 21 = [ [ ], [ [ ], [ ] ] ]
parent stack at time 21 = [ entry "MX": "Mexico", [ {"ES": "Estonia", "MX": "Mexico"}, [ ] ] ]

then the expression at time 22 = entry "MX": "Mexico"

Proof:

View as a tree | View dependent proofs | Try proving it

Given

1	expression state at time 21 = "iterate_args"
2	arguments stack at time 21 = [ [ ], [ [ ], [ ] ] ]
3	parent stack at time 21 = [ entry "MX": "Mexico", [ `{"ES": "Estonia", "MX": "Mexico"}`, [ ] ] ]

Proof Table

#	Claim	Reason
1	the expression at time (21 + 1) = entry "MX": "Mexico"	if expression state at time 21 = "iterate_args" and arguments stack at time 21 = [ [ ], [ [ ], [ ] ] ] and parent stack at time 21 = [ entry "MX": "Mexico", [ `{"ES": "Estonia", "MX": "Mexico"}`, [ ] ] ], then the expression at time (21 + 1) = entry "MX": "Mexico" (Iterate Arguments Finished Rule)
2	21 + 1 = 22	21 + 1 = 22 (Fixed Value Statement)
3	the expression at time (21 + 1) = the expression at time 22	if 21 + 1 = 22, then the expression at time (21 + 1) = the expression at time 22 (Substitution)
4	the expression at time 22 = entry "MX": "Mexico"	if the expression at time (21 + 1) = the expression at time 22 and the expression at time (21 + 1) = entry "MX": "Mexico", then the expression at time 22 = entry "MX": "Mexico" (Transitive Property of Equality Variation 2)

Comments

Please log in to add comments